The length of a line segment joining the points A (2,-3) and b(10,y) 10 unit find the value of y if A and B are in different quadrant
Answers
Answered by
0
A(2,-3) and B(10,y)
a=2,B=-3
a'=10,b'=y
(a-a')^2+(y-y')^2 = (distance)^2
(2-10)^2+(-3+y)^2=(10)^2
(-8)^2+(9-6y+y^2)=100
64+9-6y+y^2=100
y^2-6y+73-100=0
y^2-6y-27=0
y^2-9y+3y-27=0
y(y-9)+3(y-9)=0
(y+3)(y-9)=0
y=-3 , | y=9
(discarded, because both points | therefore, y= 9
are not in same quadrant) |
A(2,-3) , B(10,9)
a=2,B=-3
a'=10,b'=y
(a-a')^2+(y-y')^2 = (distance)^2
(2-10)^2+(-3+y)^2=(10)^2
(-8)^2+(9-6y+y^2)=100
64+9-6y+y^2=100
y^2-6y+73-100=0
y^2-6y-27=0
y^2-9y+3y-27=0
y(y-9)+3(y-9)=0
(y+3)(y-9)=0
y=-3 , | y=9
(discarded, because both points | therefore, y= 9
are not in same quadrant) |
A(2,-3) , B(10,9)
Similar questions