The length of a metal rod at 0°c is 1.5m. Determine the temperature of the rod when its length has increased by 1.5mm. Linear expansivity of the rod is 5×10^-6°c-1
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Answer:
∆L = L alpha ∆T
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Answer:Tf=200°c
Explanation:♢T=alphaLi♢T
1.5×10^-3=5×10^-6×1.5 (Tf-0°c)
0.0015m=0.0000075°cM (Tf-0°c)
0.0015m=0.0000075°cMTf
0.0015m÷0.0000075°cM
Tf=200°c
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