The length of a metal rod at 20 degree Celsius is 1 m when the temperature is increased to 50 degree Celsius the expansion is 1 mm.If the length is to be decreased by 1 mm ,the temperature to which it should be cooled is
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Answer:
-100c
Explanation:
Correct option is C)
l1l2−l1=α(50−20)
11×10−3=α(30)
α=3.34×10−5/0c
1−1×10−3=α(T−20)
T=(−30+20)=−100c
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