Physics, asked by shauryabaranwal4800, 11 months ago

The length of a metallic rod is 5 m at 0°C and
becomes 5.01 m, on heating upto 100°C. The
linear expansion of the metal will be :
(a) 2.33 × 10⁻⁵/°C (b) 6.0 × 10⁻⁵/°C
(c) 4.0 × 10⁻⁵/°C (d) 2.0 × 10⁻⁵/°C

Answers

Answered by Anonymous
4

\huge\underline{\underline{\bf \orange{Question-}}}

The length of a metallic rod is 5 m at 0°C and becomes 5.01 m, on heating upto 100°C. The linear expansion of the metal will be :

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Initial length of metal rod {\sf l_i}= 5m
  • At temperature {\sf (T_1)} = 0°C
  • Final length {\sf l_f} = 5.01m
  • At temperature {\sf (T_2)} = 100°C

\large\underline{\underline{\sf To\:Find:}}

  • Linear expansion \alpha

\large{\boxed{\bf \blue{\alpha = \dfrac{l_f-l_i}{l_i×\triangle T}} }}

\implies{\sf \dfrac{5.01-5}{5×(100-0)} }

\implies{\sf  \dfrac{0.01}{5×100}}

\implies{\sf \dfrac{10^{-2}}{5×10^2}}

\implies{\sf \dfrac{0.2×10^{-2}}{10^2}}

\implies{\sf 0.2×10^{-4} }

\implies{\bf \red{\alpha=2×10^{-5}/°C}}

\huge\underline{\underline{\bf \orange{Answer-}}}

Option (d)

The linear expansion of the metal will be {\bf \red{2×10^{-5}/°C}}.

Answered by Anonymous
0

Answer:

2×10  −5  /  0  C

Explanation:

ΔL=Lo∝ΔT

ΔT/Lo∝ΔT  =  D

5×100 0.01

=2×10  −5  /  0  C

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