the length of a minute hand of a clock is 14 cm find the area swept by the minute hand in 10 minutes
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Answered by
13
radius=14cm
area swept by minute hand=10mins
{60 minutes=360 degrees
1 minute =360/60 =6 degrees
for 10 minutes 6×10 =60 degrees}
so angle described by minute hand in
10mins, theta =60degrees
so area swept in 10 mins =πr² theta/360
=22/7×14×14×60/360
=308/3
=102 2/3( in mixed fraction)
pls mark it brainliest
area swept by minute hand=10mins
{60 minutes=360 degrees
1 minute =360/60 =6 degrees
for 10 minutes 6×10 =60 degrees}
so angle described by minute hand in
10mins, theta =60degrees
so area swept in 10 mins =πr² theta/360
=22/7×14×14×60/360
=308/3
=102 2/3( in mixed fraction)
pls mark it brainliest
Nikki57:
Correct answer :)
Answered by
17
Hey!
____________________________
Radius= 14cm
Area swept in 10 minutes =?
We know,
60 min= 360°
1 min = 360/60= 6°
10 min = 10×6=60°
Area swept in 10 min= πr^2 θ/360
= 3.14×14×14× 60/360
=308/3
____________________________
Hope it helps...!!!
____________________________
Radius= 14cm
Area swept in 10 minutes =?
We know,
60 min= 360°
1 min = 360/60= 6°
10 min = 10×6=60°
Area swept in 10 min= πr^2 θ/360
= 3.14×14×14× 60/360
=308/3
____________________________
Hope it helps...!!!
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