Question

the length of a minute hand of a clock is 15 cm find the area swept by the minute hand in 8 minutes quick please ​

Answer 1

Answer:

94.285cm^2

Step-by-step explanation:

R=15 ,theta =51.6

5.16/360×22/7×15×15

=94.285

Answer 2

Given: The length of the minute hand of a clock is $15cm$.

To find: The area swept by the minute hand in $8mins$.

Solution:

It is given that the length of the minute hand is $=15cm$

The angle that is made by the minute hand in $60 mins$ $=360^o$

∴ Angle made or described by the minute hand in $8 mins$ $=\frac{360}{60}*8=48^o$

Now we can say that,

The area swept by the clock in $8mins$ is = Area of the sector having an angle of $48^o$ and radius $=15cm$

∴ Area of the sector = $\frac{theta}{360}(\pi r^{2})$

$=\frac{48}{360}*(\frac{22}{7}*15*15)$

$=94.28cm^2$

Final answer:

The area swept by the minute hand in 8 minutes in $94.28cm^2$