Physics, asked by charu128, 1 year ago

the length of a minute hand of a clock is 3 cm.Find the average velocity of the tip of the minute hand when it moves during time interval from 4 p.m. to 4:15 p.m. ​

Answers

Answered by ItsSahil002
5

minute.

Speed of minutes hand=6 degrees per minute

angular distance moved by the minute hand between 

6.00 Am to 6.30 Am=30 (6 degrees ) =180 degrees

average angular velocity in this period is 

π/1800 rad/s

so, angular velocity of the tip of minute hand will be

4.5 x π/1800

=0.0025πcm/s

similarly for the second part the minute hand will cover( 6 

degrees)(750)=4500 degrees

Angular velocity in this period is

25π/750x60=π/1800 rad/s

Average velocity of the tip of minute hand will be

4.5 x π/1800=0.0025πcm/s

Answered by anucparuchuri
0

Answer:

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Explanation:

Speed of minutes hand=6 degrees per minute

angular distance moved by the minute hand between  

6.00 Am to 6.30 Am=30 (6 degrees ) =180 degrees

average angular velocity in this period is  

π/1800 rad/s

so, angular velocity of the tip of minute hand will be

4.5 x π/1800

=0.0025πcm/s

similarly for the second part the minute hand will cover( 6  

degrees)(750)=4500 degrees

Angular velocity in this period is

25π/750x60=π/1800 rad/s

Average velocity of the tip of minute hand will be

4.5 x π/1800=0.0025πcm/s

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