the length of a minute hand of a clock is 3 cm.Find the average velocity of the tip of the minute hand when it moves during time interval from 4 p.m. to 4:15 p.m.
Answers
minute.
Speed of minutes hand=6 degrees per minute
angular distance moved by the minute hand between
6.00 Am to 6.30 Am=30 (6 degrees ) =180 degrees
average angular velocity in this period is
π/1800 rad/s
so, angular velocity of the tip of minute hand will be
4.5 x π/1800
=0.0025πcm/s
similarly for the second part the minute hand will cover( 6
degrees)(750)=4500 degrees
Angular velocity in this period is
25π/750x60=π/1800 rad/s
Average velocity of the tip of minute hand will be
4.5 x π/1800=0.0025πcm/s
Answer:
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Explanation:
Speed of minutes hand=6 degrees per minute
angular distance moved by the minute hand between
6.00 Am to 6.30 Am=30 (6 degrees ) =180 degrees
average angular velocity in this period is
π/1800 rad/s
so, angular velocity of the tip of minute hand will be
4.5 x π/1800
=0.0025πcm/s
similarly for the second part the minute hand will cover( 6
degrees)(750)=4500 degrees
Angular velocity in this period is
25π/750x60=π/1800 rad/s
Average velocity of the tip of minute hand will be
4.5 x π/1800=0.0025πcm/s