The length of a minute hand of a clock is 6cm fins the area wept by the minute hand i 10 minutes
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According To clock design of minute hand 60min=360°(it completed whole rotation in 60 min) 10 min=60° Area swept=πr²x/360 Where r=6cm,x=60°,π=22/7 Solving this we get 22×(6)²×60/360×7 =113.14cm²
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