The length of a minute hand of a wall clock is 10.5 cm and that of the Hour hand is 8.5 cm find the area between the track covered by the tips of minute hand and hour hand in one complete revolution (takephy=3.14)
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Answer:
119.4 sq.cm
Step-by-step explanation:
Given: length of minute hand (r)=10.5cm
length of hour hand (R)=8.5cm
area covered by minute hand= π×r×r
=3.14×10.5×10.5=346.2 sq.cm
area covered by hour hand=π×R×R
=3.14×8.5×8.5=226.8 sq.cm
area of track between them = area covered by minute hand-area covered by hour hand
= 346.2-226.8=119.4 sq.cm
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