Question

The length of a minute hand of a wall clock is 8.4cm find the area swept by it in half an hour

Answer 1

Answer:

110/88 cm²

Step-by-step explanation:

In half an hour, minute hand moves across half of the clock = half of area of circle= πR²/2

given that R = 8.4 cm

∴ Area swept = (1/2) × 8.4 × 8.4 × 22/7

= 4.2 × 1.2 ×22 =110/88 cm²

Answer 2

hey mate here is ur answer

the length of the clock can be the radius

radius = 8.4 cm

the area swept half an hour
= area of semicircular

$area \: of \: semicircle \: = \: \frac{\pi {r}^{2} }{2} \\ \\ = \frac{22 \times 8.4 \times 8.4}{7 \times 2} \\ \\ = \frac{1552.32}{14} \\ \\ = 110.88 {cm}^{2}$


hope this helps you

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