the length of a pendulum is (1.5+-0.01)m and the acceleration due to gravity is taken in to account as (9.8+-0.1)ms-2 . Calculate the time period of the pendulum with uncertainty in it.
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Answer:
l=1.12m; g=9.8ms
−2
; T=?
T=2π
g
l
=
7
2×22
9.8
1.12
=
7
44
0.114
=
7
44
×0.338=2.12s
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