Question

the length of a pendulum is (1.5+-0.01)m and the acceleration due to gravity is taken in to account as (9.8+-0.1)ms-2 . Calculate the time period of the pendulum with uncertainty in it.

Answer 1

Answer:

l=1.12m; g=9.8ms

−2

; T=?

T=2π

g

l

=

7

2×22

9.8

1.12

=

7

44

0.114

=

7

44

×0.338=2.12s

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