Question

The length of a pendulum is (1.5 + 0.01) m and the acceleration due to
gravity is taken into account as (9.8 +0.1) m s?. Calculate the time period
of the pendulum with uncertainty in it.

Answer 1

Answer:

first you mark me as brainly

Answer 2

Answer:

2.45 + 0.8%

Explanation:

% of l =0.01 / 1.5 * 100 %

= 0.67%

% of g= 0.1 / 9.8 * 100%

=1.02 %

total % age = 0.67+1.02 % = 1.69%

1. As k = 2 pi and is constant

  $T = 2\pi \sqrt l/g$

% of uncertainity= 1/2 (1.69%)

=  0.8 %

T = $T^{2} = 4\pi ^{2} *l/g$

$T^{2} = \sqrt{6.04$

T = 2.45