The length of a plain penclytum is found to be lo by a scale measuring 1mm minimum- O clock with el resoulation Fib OF I gives 9 by meusuring the time time for loo oscillutions . so the value of the following is 4 =(9&ns* 10 )
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Explanation:
T=
n
t
and ΔT=
n
Δt
∴
t
ΔT
×100=
t
Δt
×100
=
2×100
0.1
×100=0.05%
l
Δl
×100=
100cm
0.1cm
×100=0.1%
Now, T=2π
g
l
⇒g=
T
2
4π
2
l
∴ % error in g=(% error in l)+2(% error in T)
=0.1% +2(0.05%)=0.2%
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