The length of a plastic box is 1.7m, width is 1.5m and is 0.65m high. What is the longest rod that can be placed in the box? Find its TSA and CSA
MisterMeow:
it's be the diagonal of that box ... :P .. sry but too lazy to solve
Answers
Answered by
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TSA OF THE BOX =2lbh =2*1.7*1.5*0.65
=3.315m
CSA OF THE BOX =2h(l+b) =2*0.65(1.7+1.5)
=3.17m
=3.315m
CSA OF THE BOX =2h(l+b) =2*0.65(1.7+1.5)
=3.17m
Answered by
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given :
length = 1.7 m
width = 1.5 m
height = 0.65 m
need to find out :
1. TSA of the box
2. CSA of the box
3. the longest rod that can be placed in the box
solution :
1. TSA of the box :
TSA of cuboid = 2 ( lw + hw + hl )
⇒ 2 ( 1.7 * 1.5 + 0.65 * 1.5 + 0.65 * 1.7 )
⇒ 2 ( 9.265 )
⇒ 18.53 m ²
2. CSA of the box :
CSA of cuboid = 2h ( l + b )
⇒ 2 * 0.65 ( 1.7 + 1.5 )
⇒ 2 * 0.65 ( 3.2 )
⇒ 1.3 ( 3.2 )
⇒ 4.16 m ²
3. the longest rod that can be placed in the box :
formula = √( l² + b² + h² )
⇒ 2.268 m ²
∴ the longest rod that can be fit in the box would be of 2.268 m ²
length = 1.7 m
width = 1.5 m
height = 0.65 m
need to find out :
1. TSA of the box
2. CSA of the box
3. the longest rod that can be placed in the box
solution :
1. TSA of the box :
TSA of cuboid = 2 ( lw + hw + hl )
⇒ 2 ( 1.7 * 1.5 + 0.65 * 1.5 + 0.65 * 1.7 )
⇒ 2 ( 9.265 )
⇒ 18.53 m ²
2. CSA of the box :
CSA of cuboid = 2h ( l + b )
⇒ 2 * 0.65 ( 1.7 + 1.5 )
⇒ 2 * 0.65 ( 3.2 )
⇒ 1.3 ( 3.2 )
⇒ 4.16 m ²
3. the longest rod that can be placed in the box :
formula = √( l² + b² + h² )
⇒ 2.268 m ²
∴ the longest rod that can be fit in the box would be of 2.268 m ²
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