the length of a ractangular is 5 mtr more than its breadth. if perimeter of the hall is 74 mtr, find its length and breadth
Answers
Answered by
3
Hey!!!!!
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Let the length and breadth of the rectangle be x and y respectively.
Then ATQ,
=>x - 5 = y----------(1)
Perimeter = 74m
=> 2(x + y) = 74
=> x + x - 5 = 37 (From (1))
=> 2x = 42
=> x = 21
Using in (1)
=> y = 21 - 5
=> y = 16
Thus the length is 21m and breadth is 16m
____________
Hope this helps ✌️
_____________
Let the length and breadth of the rectangle be x and y respectively.
Then ATQ,
=>x - 5 = y----------(1)
Perimeter = 74m
=> 2(x + y) = 74
=> x + x - 5 = 37 (From (1))
=> 2x = 42
=> x = 21
Using in (1)
=> y = 21 - 5
=> y = 16
Thus the length is 21m and breadth is 16m
____________
Hope this helps ✌️
Answered by
2
heya !!
here is ur answer
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Given :- length = breadth + 5 ( it is given 5 mtr more than in question.
♦ breadth = x
♦ length = x +5
perimeter = 2( l+B)
➡ substituting the Values :-
Given perimiter = 74 mtr
➡ 74 = 2( X+5 +X )
➡ 74 = 2(2x+5)
➡ 74 = 4x + 10
➡ 74 - 10 = 4x
➡ 64 = 4x
➡ X = 64 / 4
➡ X = 16
so breadth = 16 mtr.
length = 16+5 = 21 mtr.
verification :-
74 = 2( 16+21)
74 = 2( 37)
74 = 74
hence proved.
======================
hope it helps u..!!
here is ur answer
=======================
Given :- length = breadth + 5 ( it is given 5 mtr more than in question.
♦ breadth = x
♦ length = x +5
perimeter = 2( l+B)
➡ substituting the Values :-
Given perimiter = 74 mtr
➡ 74 = 2( X+5 +X )
➡ 74 = 2(2x+5)
➡ 74 = 4x + 10
➡ 74 - 10 = 4x
➡ 64 = 4x
➡ X = 64 / 4
➡ X = 16
so breadth = 16 mtr.
length = 16+5 = 21 mtr.
verification :-
74 = 2( 16+21)
74 = 2( 37)
74 = 74
hence proved.
======================
hope it helps u..!!
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