the length of a reactangular field is 3 times its breadth if the breadth of the field is 7/2m,find the perimeter of the rectangle.
Answers
Answered by
2
length = 3*breadth
Given that breadth = 7/2
Then, length = (3*7/2) = 21/2
Now,
we know that perimeter of rectangle= 2(length+breadth)
here,
perimeter of rectangle = 2(7/2 + 21/2)
perimeter of rectangle = (2*7/2) + (2*21/2)
perimeter of rectangle = 7+21
perimeter of rectangle = 28m
i hope this will help you
-by ABHAY
Given that breadth = 7/2
Then, length = (3*7/2) = 21/2
Now,
we know that perimeter of rectangle= 2(length+breadth)
here,
perimeter of rectangle = 2(7/2 + 21/2)
perimeter of rectangle = (2*7/2) + (2*21/2)
perimeter of rectangle = 7+21
perimeter of rectangle = 28m
i hope this will help you
-by ABHAY
Answered by
0
Breadth =7/2m
Then length 3 times of breadth
3*7/2=>21/2
P=2(l+b)
=2(21/2+7/2)
=2(21+7/2)
=2(28/2)
=2*14
=28mtr
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