Math, asked by dejohnsri, 1 day ago

THE LENGTH OF A RECTANGLAR FLOWER BED IS (2x - 1) METERS AND THE WIDTH IS (x + 2) METERS FIND THE PERIMETER OF THIS FLOWER BED IN TERMS OF x3​

Answers

Answered by raben
0

LENGTH OF A RECTANGLAR FLOWER BED= (2x-1)m

WIDTH OF A RECTANGLAR FLOWER BED=(x+2) m

PERIMETER OF THIS FLOWER BED= 2(l+b)

= 2(( 2x-1)+(x+2))

=2(3x+1)

=6x+2

PERIMETER= (6x+2)m

Hope it helps you.

Answered by himanshu2006jangir
0

Answer:

2(3x+1)

Step-by-step explanation:

LENGTH=2X-1

WIDTH=X+2

PERIMETER OF RECTANGLE=2(L+B)

""". """"". """"""=2{(2X-1)+(X+2)}

""""". """"""""". ""=2{2X-1+X+2}

""""". """"". """""=2(3X+1)

Similar questions