Question

The length of a rectangle are 37 / 11 and 73/13 . Find the perimeter and area of rectangle

Answer 1

Answer:

Perimeter= 2(l+b)

Perimeter of rectangle = 2*(37/11 + 73/13)

= 17.95 units

Area = l*b

Area of rectangle = 37/11*73/13

= 18.88 units

Answer 2

Step-by-step explanation:

Given that,

length of the rectangle is (l) =37/11

breadth of the rectangle is (b) = 73/13

perimeter of the rectangle is (P)= 2(l+b)

⇒P=2(37/11+73/13)

⇒P=2((13)(37)+(11)(73))/143

⇒P=2(481+803)/143

⇒P=2(1284)/143

⇒P=2568/143

area of rectangle is (A)=l×b

⇒A=37/11×73/13

⇒A=2701/143

∴perimeter(P)=2568/143 units

  area(A)=2701/143 sq.units

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