The length of a rectangle exceed its width by 4 m if its perimetr is 40 m find its dimemsion
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Answered by
3
Step-by-step explanation:
let w=x l=x+4
perimeter of rectangle =40
2(l+w)=40
2(x+4+x)=40
2x+4=20
2x=20-4
x=16÷2
x=8
therefore dimensions of rectangle are
8,12
Answered by
1
Answer:
Length is 12m and width is 8m.
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