the length of a rectangle exceedits width by 5 if the width is increased by 1 m and the length is decreased by 2 m the area of a new rectangle is 4 sq metre less than the area of original rectangle find the dimensions of the original rectangle
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Let the width of original rectangle be x
=> length of original rectangle = 5 + x
=> area of original = Length × breadth
= (5 + x)x
= x² + 5x
Now new breadth = x + 1
New length = 5 + x - 2 = 3 + x
=> new area = (3 + x)(x + 1)
= 3x + 3 + x² + x
= x² + 4x + 3
Given that the new area is less than the original by 4
=> x² + 5x = x² + 4x + 3 + 4
=> x² + 5x = x² + 4x + 7
=> x² + 5x - x² - 4x = 7
=> x = 7
=> width = 7
=> original length = 5 + x = 5 + 7 = 12
So your answer
width = 7 m
Length = 12 m
Hope it helps dear friend
=> length of original rectangle = 5 + x
=> area of original = Length × breadth
= (5 + x)x
= x² + 5x
Now new breadth = x + 1
New length = 5 + x - 2 = 3 + x
=> new area = (3 + x)(x + 1)
= 3x + 3 + x² + x
= x² + 4x + 3
Given that the new area is less than the original by 4
=> x² + 5x = x² + 4x + 3 + 4
=> x² + 5x = x² + 4x + 7
=> x² + 5x - x² - 4x = 7
=> x = 7
=> width = 7
=> original length = 5 + x = 5 + 7 = 12
So your answer
width = 7 m
Length = 12 m
Hope it helps dear friend
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