Question

The length of a rectangle exceeds it breadth by 9 cm if a perimeter is 54 cm find the dimensions of rectangle

Answer 1

Answer

$\boxed{\textbf{\large{length=18cm}}}$

$\boxed{\textbf{\large{</u></strong><strong><u>b</u></strong><strong><u>r</u></strong><strong><u>e</u></strong><strong><u>a</u></strong><strong><u>d</u></strong><strong><u>t</u></strong><strong><u>h</u></strong><strong><u>=</u></strong><strong><u>9</u></strong><strong><u>c</u></strong><strong><u>m</u></strong><strong><u>}}}$

Given

perimeter of rectangle = 54 cm

l(length) = 9+b(breadth)

Explanation

☑ As a given, length of rectangle exceeds it's breadth by 9cm

l(length) = 9+b(breadth)

were ,

l is length

b is breadth

we know

☑ perimeter of rectangle =

perimeter of rectangle = 2 ( l + b)

so,

perimeter of rectangle

= 2((9+b)+b)

54 = 2(9+2b)

54 = 18 + 4b

54-18 = 4b

36/4 = b

b(breadth) = 9 cm

☑ so, length will be...

perimeter of rectangle =

2 ( l + b)

54 = 2 ( l + 9 )

54 = 2l + 18

(54 - 18)/2 = l

l(length) = 18cm

☑ Therefor the dimensions of the rectangle are

$\boxed{\textbf{\large{length=18cm}}}$

$\boxed{\textbf{\large{breadth=9cm}}}$