Question

The length of a rectangle exceeds it's width by 6 m.If it's perimeter 44m ,find its dimensions​

Answer 1

Answer:

length = 14m, width = 8 m

Step-by-step explanation:

let width be 'x'

Given,

width = x

length = 6+x

Perimeter = 44 m

Perimeter of a rectangle = 2(l+b)

2(l+b) = 44m

Substitute the values in the equation:

2(6+x+x) = 44

2(6+2x) = 44

12 + 4x = 44

4x = 44-12 = 32

x = 32/4 = 8

Therefore,

width = x = 8m//

length = 6+x = 8+6 = 14 m//

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Answer 2

Answer:

Here is your answer...

Step-by-step explanation:

Let the width of rectangle be x m

then, length of rectangle=(x+6)m

Perimeter is given as 44m

then A/q,

Perimeter of rectangle=2(l+b)

or, 44 = 2{(x+6)+x}

or,. 44= 2(2x+6)

or,. 44/2= 2x+6

or,. 22-6= 2x

or,. 16=2x

or,. 16/2= x

therefore, x= 8m

Hence, length of rectangle=14m

breadth of rectangle=8m

Hope it helps you.