Question

The length of a rectangle exceeds its breadth by 11 cm. If the perimeter of the rectangle is 126 cm, find its dimensions.​

Answer 1

Answer:

let the length of the rectangle be X

breadth=x-11 perimeter = 126

A/Q

126 = 2(X+X-11)

126 =4X -22

4X =148

X=37 cm

breadth = 37-11

=26 cm

Step-by-step explanation:

please mark it as brainliest

Answer 2

$\bf{\underline{Question:-}}$

The length of a rectangle exceeds its breadth by 11 cm. If the perimeter of the rectangle is 126 cm, find its dimensions.

$\bf{\underline{Given:-}}$

• The length of a rectangle exceeds its breadth by 11 cm
• Perimeter of rectangle = 126cm

Let

• the breadth of the rectangle be x cm
• Length of rectangle = x + 11 cm

$\bf{\underline{Formula:-}}$

Perimeter of the rectangle = 2 ( length + breadth )

$\bf{\underline{Solution:-}}$

→ 2 ( (x + 11) + x ) = 126

→ x + 11 + x = 63

→ 2x = 52

→ x = 26

$\bf{\underline{Hence:-}}$

• Breadth of the rectangle X = 26 cm

• Length of the rectangle X + 11 = 26 + 11 = 37 cm