Question

the length of a rectangle exceeds its breadth by 3 CM if each of the length and breadth are increased by 2 cm the area of a new rectangle with 58 CM square more than that of the original rectangular find the length of breath of the original rectangle

Answer 1

let length be ...x

breadth be...x-3

A to Q

(x+2)×(x-3+2)=(x)×(x-3)+58

(x+2)×(x-1)=x^2 - 3x + 58

x^2 + x - 2=x^2 -3x+58

4x=58+2

4x = 60

x=15

length=15

breadth=12

Answer 2

Let the length be (x + 3)
Let the breadth be x

Area of rectangle = L * B

= (x + 3) * x

= x^2 + 3x

If length and breadth are increased by 2cm

New length = (x + 3 + 2) = (x + 5)
New breadth = ( x + 2)

New area = L * B

= (x + 5)(x + 2)

= x^2 + 2x + 5x + 10

= x^2 + 7x + 10

New rectangle area is 58cm^2 more than original one.

x^2 + 7x + 10 = x^2 + 3x + 58

4x = 48

x = 12

Length of original rectangle = (x + 5) = (12+5)

= 17cm

Breadth of original rectangle = (x + 2) = (12+2)

= 14cm



Thanks