The length of a rectangle exceeds its breadth by 3cm
Answers
Answer:
Step-by-step explanation:
let breadth of the triangle = x
But length exceeds its breadth by 3cm
So the length = ( x + 3 ) cm
Let's assume the breadth of the rectangle be x cm
The length of the rectangle = x + 3 cm
It is given that the length and breadth of the rectangle is increased by 2.
Now, the breadth of the rectangle = x + 2
The length of the rectangle = x + 3 + 2 = x + 5
It is also given that the area of the rectangle is 70 sq. cm
Therefore, the area of the rectangle = length x breadth = (x + 2)(x + 5) = 70
⇒ x2 + 5x + 2x + 10 = 70
⇒ x2 + 7x = 70 - 10
⇒ x2 + 7x = 60
⇒ x2 + 7x - 60 = 0
⇒ x2 + 12x - 5x - 60 = 0
⇒ x( x + 12) -5(x + 12) = 0
⇒ ( x + 12) (x - 5) = 0
either, or,
(x + 12 = 10 x - 5 = 0
⇒ x = 10 - 12 = -2 ⇒ x = 5
The breadth of a reactangle is never negative, therefore the value of x = 5 cm
Hence, the breadth of the rectangle = 5 cm
The length of the rectangle = 5 + 3 = 8 cm