Math, asked by parulvats3458, 1 year ago

The length of a rectangle exceeds its breadth by 3cm

Answers

Answered by Nєєнα
1

Answer:

Step-by-step explanation:

let breadth of the triangle = x

But length exceeds its breadth by 3cm

So the length = ( x + 3 ) cm

Answered by shaidhrees
1

Let's assume the breadth of the rectangle be x cm

The length of the rectangle = x + 3 cm

It is given that the length and breadth of the rectangle is increased by 2.

Now, the breadth of the rectangle = x + 2

The length of the rectangle = x + 3 + 2 = x + 5

It is also given that the area of the rectangle is 70 sq. cm

Therefore, the area of the rectangle = length x breadth = (x + 2)(x + 5) = 70

⇒ x2 + 5x + 2x + 10 = 70

⇒ x2 + 7x = 70 - 10

⇒ x2 + 7x = 60

⇒ x2 + 7x - 60 = 0

⇒ x2 + 12x - 5x - 60 = 0

⇒ x( x + 12) -5(x + 12) = 0

⇒ ( x + 12) (x - 5) = 0

either, or,

(x + 12 = 10 x - 5 = 0

⇒ x = 10 - 12 = -2 ⇒ x = 5

The breadth of a reactangle is never negative, therefore the value of x = 5 cm

Hence, the breadth of the rectangle = 5 cm

The length of the rectangle = 5 + 3 = 8 cm

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