Question

The length of a rectangle exceeds its breadth by 4 cm .if the length and breadth both are increased by 3cm,the area will be 81cmsquare more than that of the given rectangle find the length and breadth of the given rectangle.

Answer 1

let the breadth be x.
length=x+4
area=l×b=x×(x+4)=x²+4x
A.T.C
if both length and width of the rectangle are increased by 3 then
length=x+4+3=x+7
width=x+3
area=(x+3)(x+7)=x²+10x+21
A.T.C
x²+4x+81=x²+10x+21
then
4x+81=10x+21
then
10x-4x=81-21
then
6x=60
then
x=10
width=x=10cm
length=(x+4)=10+4=14cm
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Answer 2

Answer:

Let the breadth be x

So, the length is (x+4)

Area = x(x+4) = x*x + 4x

Now the length and breadth is increased by 3

So, breadth = (x+3) and Length = (x+7)

Area = (x+3)(x+7) = x*x + 10x +21

According to Question

New area = Old area + 81

x*x + 10x + 21 = x*x + 4x + 81

x*x - x*x + 10x - 4x = 81 - 21

6x = 60

x = 60/6

x = 10 = Breadth

(x+4) = (10 + 4) = Length

So, Answer =

Breadth = 10

Length = 14

Step-by-step explanation: