the length of a rectangle exceeds its breadth by 4 m find the dimensions of the rectangle if its perimeter is 084 m
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Answer:
l = 23m
b = 19m
Step-by-step explanation:
let,
breadth= b
ATQ, length= l = b+4m
P of rectangle = 2 ( l + b ) = 084m
=> 2 ( b + 4 + b ) = 084m
2 ( 2b + 4 ) = 084m
( 2b + 4 ) = 84/2 = 42
2b = 42 - 4 = 38
b = 38/2 = 19m
l = b + 4 = 19 + 4 = 23m
P.S. hope it helps !
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