The length of a rectangle exceeds its breadth by 4m. If the perimeter of the rectangle is 84 m, find the length and breadth of the rectangle solutio ns
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4
Let the Breadth of rectangle be a
Length = a + 4
Perimeter = 2 (Length + Width)
84 = 2 ( a + a + 4)
=> 84 = 2 ( 2a + 4)
=> 42 = 2a + 4
=> 2a = 38
=> a = 19
Breadth = 19 m
Length = 23 m
Length = a + 4
Perimeter = 2 (Length + Width)
84 = 2 ( a + a + 4)
=> 84 = 2 ( 2a + 4)
=> 42 = 2a + 4
=> 2a = 38
=> a = 19
Breadth = 19 m
Length = 23 m
Answered by
4
Heya user
Here's your answer :-
Given that :-
Length exceeds its breadth by 4m.
>>Let breadth be x
>>then length is x+4
⇒perimeter = 2(l+b)
⇒2(x+x+4)=84
⇒2(2x+4)=84
⇒42=2x+4
⇒2x =38
⇒X =38/2
⇒19
∴ length =x+4 > 19+4 =23m
Breadth= x = 19m
Have a great day ahead ^_^
Here's your answer :-
Given that :-
Length exceeds its breadth by 4m.
>>Let breadth be x
>>then length is x+4
⇒perimeter = 2(l+b)
⇒2(x+x+4)=84
⇒2(2x+4)=84
⇒42=2x+4
⇒2x =38
⇒X =38/2
⇒19
∴ length =x+4 > 19+4 =23m
Breadth= x = 19m
Have a great day ahead ^_^
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