the length of a rectangle exceeds its breadth is 5 cm if the length and breadth are increased by 1 centimetre the area increased by 34 CM square find the length and breadth of a rectangle
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Answer:
let the breadth of the rectangle be x cm
then ATQ, length=x+5 cm
area1=l*b
area1=(x*(x+5))
area1=(x^2+5x)cm^2
again ATQ,
length = (x+5)+1 cm
length=(x+6)cm
breadth=(x+1)cm
area2=l*b
area2=(x+6)(x+1)
area2=(x^2+7x+6)cm^2
ATQ
area1+34=area2
x^2+5x+34=x^2+7x+6
7x-5x=34-6
2x=28
×=14cm
therefore;
breadth =14cm
and length=19cm
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