Question

the length of a rectangle exceeds its width by 2 m if the perimeter is 20 n find its dimensions and its area​

Answer 1

Step-by-step explanation:

perimeter of rectangle = 2(length +breath)

let width be X. therefore length=X+2

therefore x + x +2 = 20

2x = 18

X= 9

therefore length = x+2=9+2= 11m

width = 9m

therefore area of rectangle = length × breath= 11× 9 = 99 sqm