Question

The length of a rectangle exceeds its width by 3 m. If the width is increased by 4 m and the length is decreased by 6 m, the area is decreased by 22m2. Then length of the rectangle is
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Answer 1

Width= w…(w1)

Length= w+3…(L1)

Area (A1) = w(w+3)

From part (ii)

Width= w1+4 = w+4…(w2)

Length= L1–6 = w+3–6 = w-3…(L2)

Area (A2) = (w+4)(w-3)

Given, old area (A1) - new area (A2) is 22 sq. m.

Therefore,

A1- A2= 22

w(w+3) - [(w+4)(w-3)] = 22

w²+ 3w - w²- w+ 12= 22

2w= 10

OR, w= 5

Width (w)= 5

Length (w+3)= 8

Good Day!