the length of a rectangle exceeds its width by 3m. if the width is increased by 4m and the length is deacreased by 6m,the area is decreased by 22sq.m. find the dimensions of the rectangle
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Let the original length and width in metres of the rectangle be L and W
Length exceeds width by 3m:
If the width is increased by 4m and the length decreased by 6m, let the new length and width be L' and W'.
Now, the area of rectangle with dimensions W', L' is 22 sq m less than the area of the rectangle with dimensions W, L.
And since
,After expanding and simplifying we get:
Then
So the dimensions are 8m by 5m.
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