the length of a rectangle exceeds its width by 3m . If the width is increased by 4m and the length is decreased by 6m , the area is decreased by 22 sq. m . Find the dimensions of the rectangle.
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rectangle's length = x + 3 m
rectangle's breadth = x m
Area = (x + 3) × (x) m^2
= x^2 + 3x sq.m
New length(after decrease) = (x + 3) - 6 = x - 3 m
New breadth(after increase) = (x) + 4 = x + 4 m
New Area = (x - 3)(x + 4) = x^2 + x - 12 sq.m
Given that the area is decreased by 22 sq.m...
so, The old area is bigger than new area by 22.
So, 22 + new area = old area
22 + x^2 - 12 + x =x^2 + 3x
10 + x = 3x
10 = 3x - x
x = 5
rectangle's breadth = x m
Area = (x + 3) × (x) m^2
= x^2 + 3x sq.m
New length(after decrease) = (x + 3) - 6 = x - 3 m
New breadth(after increase) = (x) + 4 = x + 4 m
New Area = (x - 3)(x + 4) = x^2 + x - 12 sq.m
Given that the area is decreased by 22 sq.m...
so, The old area is bigger than new area by 22.
So, 22 + new area = old area
22 + x^2 - 12 + x =x^2 + 3x
10 + x = 3x
10 = 3x - x
x = 5
rohan12082005:
the dimensions are.... length = x + 3 = 5 + 3 = 8
breadth = 5
but how dose it possible
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