Question

The length of a rectangle exceeds its width by 6 if its perimeter is 44 find its dimension​

Answer 1

Answer:

• The dimensions of the rectangle are 14 m and 8 m respectively.

Given:

• The length of a rectangle exceeds its width by 6 m and the perimeter of the rectangle is 44 m.

Need to find:

• The dimensions of the rectangle = ?

Solution:

Let,

• The width of the rectangle = y

Then,

• The length of the rectangle = ( y + 6 )

Formula used here:

• Perimeter = 2 × (length + breadth)

Putting the values:

➜ 44 = 2 [(y + 6 ) + y]

➜ 44 = 2 ( 2y + 6 )

➜ 44 = 4y + 12

➜ 44 - 12 = 4y

➜ 32 = 4y

➜ y = 32/4

➜ y = 8

Now,

• The width of the rectangle (y) is 8m.
• Length of the rectangle(y+6) is 14 m.

Therefore:

• The dimensions of the rectangle are 14 m and 8 m respectively.

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