the length of a rectangle exceeds its width by 6m . if its perimeter is 44m, find its dimension
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Answer:
width= X
length=X+6
perimeter=44
44=2(X+X+6)
=2(2x+6)
=4x+12
44-12= 4x
32=4x
X= 32/4
= 8
breadth = 8m
length. = 8+6
=14m
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