The length of a rectangle exceeds its width by 7m if the width is decreased by 3m and the length is decreased by 10m the area is decreased by 95 sq.m find the dimensions of the rectangle
Answers
Answered by
17
b-3Xb+7-10=bX(b+7)-95
bb-6b+9=bb+7b-95
13b=104
b=8
l=15
Answered by
0
Answer:
The Length of the rectangle was 15m and the width was 8m
Step-by-step explanation:
width = x
length = x + 7
Old area - 95 = new area
(x) (x + 7) - 95 = (x - 3) * (x + 7 - 10)
x^2 + 7x - 95 = (x - 3) (x - 3)
x^2 + 7x -95 = x^2 - 6x + 9
7x + 6x = 9 + 95
13x = 104
x = 104/13
x = 8
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