Question

The length of a rectangle exceeds its width by 7m if the width is decreased by 3m and the length is decreased by 10m the area is decreased by 95 sq.m find the dimensions of the rectangle

Answer 1

b-3Xb+7-10=bX(b+7)-95

bb-6b+9=bb+7b-95

13b=104

b=8

l=15

Answer 2

Answer:

The Length of the rectangle was 15m and the width was 8m

Step-by-step explanation:

width = x

length = x + 7

Old area - 95 = new area

(x) (x + 7) - 95 = (x - 3) * (x + 7 - 10)

x^2 + 7x - 95 = (x - 3) (x - 3)

x^2 + 7x -95 = x^2 - 6x + 9

7x + 6x = 9 + 95

13x = 104

x = 104/13

x = 8