Question

the length of a rectangle exceeds the breadth by 7cm and its area is 450 . the perimeter of the rectangle is

Answer 1

Hiii. ....friend

The answer is here,

Let the breadth be x.

Then the length => x+7.

Area => Length×breadth .

=> x (x+7) =450

$= > \: {x}^{2} + 7x - 450 = 0$

$= > \: {x}^{2} + 25x - 18x - 450 = 0$

$= > \: x(x + 25) - 18(x + 25) = 0$

$= > \: (x + 25)(x - 18) = 0$

$= > \: x = 18$

So,breadth =18 units.

Length => 18+7=25units.

Perimeter => 2 (l+b)

=> 2 (18+25)

=> 2×43

=> 86units.

:-)Hope it helps u

Answer 2

Answer :

Let the Length of the Rectangle be 'l'

and Breadth of the Rectangle be 'b'

From Question we can know that

l = b + 7

Area of a rectangle + Length * Breadth

450 = b * ( b +7 )

b² + 7b - 450 = 0

b² - 18b + 25b - 450 = 0

b ( b - 18 ) + 25 ( b - 18 ) = 0

( b - 18 ) ( b + 25 ) = 0

b = 18 or ( -25 )

Measurements cannot be negative , so Breadth is 18cm

Perimeter = 2 ( l + b )

= 2 ( b + 7 + b ) as l = b + 7

= 2 ( 2b + 7 )

= 2 ( 36 + 7 )

= 86 cm