Question

the length of a rectangle exceeds thriceuts width by 3 meters. find the dimension of the rectangle if it is area is 60sq.meter​

Answer 1

Answer:

Let b be the breadth

length =b+3

If length and breadth increased by 2cm new area is 70 sq cm more

i.e., b(b+3)+70=(b+2)(b+5)

b

2

+3b+70=b

2

+2b+5b+10

4b=60

b=15

l=15+3=18.