The length of a rectangle exceeds twice its breadth by 2 cm . If the perimeter of rectangle is 28 cm ,find the length and breadth (full method)
Answers
Step-by-step explanation:
The Length is 10 cm and Breadth is 4 cm.
Given :
Length of the Rectangle = exceeds twice its breadth by 2 cm
Perimeter of the Rectangle = 28 cm
To Find :
The Length and Breadth
Solution :
◆
Breadth as x
Length as (2x + 2)
★ Perimeter =
2(x + 2x + 2) = 28
2x + 4x + 4 = 28
6x + 4 = 28
6x = 28 - 4
6x = 24
x = 24/6
x = 4
Breadth = 4 cm
★ Value of (2x + 2)
2(4) + 2
8 + 2
10
Length = 10 cm
The Length is 10 cm and Breadth is 4 cm.
Answer:The Length is 10 cm and Breadth is 4 cm.
Given :
Length of the Rectangle = exceeds twice its breadth by 2 cm
Perimeter of the Rectangle = 28 cm
To Find :
The Length and Breadth
Solution :
◆
Breadth as x
Length as (2x + 2)
★ Perimeter =
2(x + 2x + 2) = 28
2x + 4x + 4 = 28
6x + 4 = 28
6x = 28 - 4
6x = 24
x = 24/6
x = 4
Breadth = 4 cm
★ Value of (2x + 2)
2(4) + 2
8 + 2
10
Length = 10 cm
The Length is 10 cm and Breadth is 4 cm.
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Step-by-step explanation: