Question

The length of a rectangle exceeds twice its width by 1 meter. It the area of the rectangle is 55 sq me five its length with width.

Answer 1

Hey friend , Harish here.

Here is your answer.
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Let , Width of the rectangle = x

Then, Length of rectangle = 2x + 1

Area of rectangle = Length × Width

=>                   55 = (2x + 1) × x

=>                   55 = 2x² + x

=>                   2x² + x - 55 = 0

=>                  2x² - 10x +11x - 55 = 0

=>                2x( x - 5) + 11 ( x - 5) = 0

=>                  (2x+11) ( x-5) = 0

The above equation is zero when  (x-5) = 0  (or) (2x +11) = 0

If, x - 5 = 0. Then , x = 5.

The other case cannot be taken because we get a negative value of x.
 
∴ Width of the rectangle = x = 5m
   Length of rectangle = 2x + 1 = 2 (5) + 1 =11m
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Hope my answer is helpful to u.