the length of a rectangle exeeds its breath by 4m find the dimensions of the rectangle if the perimeter is 84m
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Answered by
1
Let width of the rectangle be x metres,
Then, length = (x+4)m
Perimeter=40m.
Perimeter of a rectangle = 2(l+b)......(i)
Putting value of l and b in equation (i) we get,
⇒40=2(x+4+x)
⇒40=2(2x+4)
⇒40/2=2x+4
⇒20-4=2x
⇒16=2x
⇒x=8
Therfore,
breadth = x = 8m
and length = x+4=8+4=
12m
Then, length = (x+4)m
Perimeter=40m.
Perimeter of a rectangle = 2(l+b)......(i)
Putting value of l and b in equation (i) we get,
⇒40=2(x+4+x)
⇒40=2(2x+4)
⇒40/2=2x+4
⇒20-4=2x
⇒16=2x
⇒x=8
Therfore,
breadth = x = 8m
and length = x+4=8+4=
12m
kpop:
thank you
Answered by
0
◆HelloThere◆
let the breadth to be x
length x + 4
perimetre of rectangle = 2 [ l +b ]
= 2 [ x +4 + x ] = 84
2x + 4 = 84 / 2
2x + 4 = 42
2x = 42 - 4 = 38
2x = 38
x = 38 / 2
x = 19
breadth = 19 m [ x]
length = 23 m [x + 4 ]
let the breadth to be x
length x + 4
perimetre of rectangle = 2 [ l +b ]
= 2 [ x +4 + x ] = 84
2x + 4 = 84 / 2
2x + 4 = 42
2x = 42 - 4 = 38
2x = 38
x = 38 / 2
x = 19
breadth = 19 m [ x]
length = 23 m [x + 4 ]
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