Question

the length of a rectangle field 8meters more than it's breadth.if perimeter of it's is 108m find the dimension​

Answer 1

Answer:

breadth be x

length be x+8

According to the question

2(x+8+x)=108

=)2(2x+8)=108

=)4x+16=108

=)4x=92

=)x=23

x+8=31

Answer 2

Answer:

Let the length be x

Breath be x-8

Perimeter=108m

Since, perimeter=2(l+b)

108=2(x+x-8)

108/2=(2x-8)

54=2x-8

54+8=2x

62=2x

x=62/2

x=31

length=31m

Breath=x-8

=31-8

=23m

Note if you take length as x+8 and breath as x then also you will get the same result

108=2(x+8+x)

108/2=(2x+8)

54=2x+8

54-8=2x

2x=46

x=46/2

x=23

Breath=23m

Length=x+8

=23+8

=31m

So in the both cases answers are same so you can write using any method.