The length of a rectangle field exceeds it's by 25 mitres.If the Perimeter of the field is 154m, Find the length and breadth of the field.
Answers
Step-by-step explanation:
Given :
Length of Rectangular field exceeds its breadth by 25 m.
Perimeter of Rectangular field is 154m.
To Find :
Length and Breadth of Rectangular Field.
Solution :
\longmapsto\tt{Let\:Breadth=x}⟼LetBreadth=x
As Given that Length of the field exceeds its breadth by 25 metres .So ,
\longmapsto\tt{Length=x+25}⟼Length=x+25
Using Formula :
\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}⟼
PerimeterofRectangle=2(l+b)
Putting Values :
\longmapsto\tt{154=2(25+x+x)}⟼154=2(25+x+x)
\longmapsto\tt{\cancel\dfrac{154}{2}=2x+25}⟼
2
154
=2x+25
\longmapsto\tt{77-25=2x}⟼77−25=2x
\longmapsto\tt{52=2x}⟼52=2x
\longmapsto\tt{x=\cancel\dfrac{52}{2}}⟼x=
2
52
\longmapsto\tt\bold{x=26}⟼x=26
Value of x is 26...
Therefore :
\longmapsto\tt{Length\:of\:Field=26+25}⟼LengthofField=26+25
\longmapsto\tt\bold{51m}⟼51m
\longmapsto\tt\bold{Breadth\:of\:Field=26m}⟼BreadthofField=26m
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Given:
The perimeter of rectangle = 154m
The length exceeds breadth by 9m
To find:
Length and breadth of the rectangle
Solution:
Let us take l,b as length and breadth of the rectangle.
From given,we can write,
l = b + 9
Perimeter of the rectangle = 2 (l+b)
2 (l+b) = 154m
l +b = 154/2
l + b = 77
Substitute the value of l ,
b +9 + b = 77
2b = 77 -9
2b = 68
b = 34 m
Substitute the value of b ,
l => 34 + 9
l => 43 m
The length and breadth of a rectangle are 43m,34m
....