Question

The length of a rectangle field is 8 meters less than twice the third side of the perimeter of the rectangular field is 56 find the length and width

Answer 1

Let the breadth of rectangle(b) = x m
then length(l) = (2x-8) m
A/q,
      perimeter of rectangle = 56 m
⇒  2(l+b) = 56
⇒  2(2x-8+x) = 56
⇒    3x-8 = 28
⇒     3x =28+8
⇒     x = 36/3 = 12 m
therefore length(l) = 2x-8 =2×12 - 8 =16 meters
               breadth(b) = x = 12 meters