the length of a rectangle field is given in the figure is 2 times width. perimeter of the field is 180 m. find the dimensions of the field........ pls solve this question and who ever soves it with explanation and methos i will mark them as the brainliest.............
Answers
AnSwer -:
The length of the rectangle-: 60 cm
The breadth of rectangle-: 30 cm
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Explanation-:
Formula of perimeter of Rectangle-:
“P= 2(l+b)”
P = Perimeter
L = length
B = Breadth or width
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Given,
Perimeter of Rectangle-: 180m
And ,
Length is twice to its breadth
To find,
The dimensions of Rectangle
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Solution-:
Let the width of a rectangle be y
Then ,
According to the question,
Length of rectangle-: 2 y
Formula of perimeter of Rectangle-:
“P = 2 (l+b)”
P = Perimeter = 180n
L = length = 2 y
B = Breadth = y
Then,
180 = 2(y+2y)
2y + y = 180/2
3y = 90
Y = 90/3
Y = 30
Therefore,
The breadth of rectangle = y = 30m
The length of rectangle= 2y = 2 x30
= 60 cm
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The length of the rectangle-: 60 cm
The breadth of rectangle-: 30 cm
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Verification-:
Formula of Perimeter of Rectangle-:
“P = 2(l +b)”
P = Perimeter = 180 m
L = length = 60 m
B = breadth = 30 m
Then ,
2 (60 + 30) = 180
2 x 90 = 180
180 = 180
Therefore,
LHS = RHS
Hence verified
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Rectangle-: A rectangle is a quadrilateral
with four right angles.
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