Question

The length of a rectangle field is twice its breath if the perimeter of the field is 222 meter then find the length and breath of the field

Answer 1

Answer:

Let the breadth be a and hence length should be 2a( twice of a ).

Sides of the Rectangle = 2a and a

We know that,

Perimeter of the rectangle , 222 m

As We know that,

Perimeter of the rectangle = 2(length + breadth)

Substituting the values in the above formula, we get,

= > 222 = 2( 2a + a )

= > 222 = 2( 3a )

= > 222 = 6a

= > 222 / 6 = a

= > 37 = a

Hence,

breadth = a = 37 m

length = 2a = 2(37m) = 74 m

Breadth of the field is 37 m and length is 74 m

Answer 2

$\huge\sf\pink{Answer}$

☞ Length of the rectangle field is 74 m and the Breadth of the rectangle field is 37 m

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ The length of a rectangle field is twice its breadth

✭ The perimeter of the field is 222 m

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ Length and breadth?

$\rule{110}1$

$\huge\sf\purple{Steps}$

Let us assume that,

➝ Length of the rectangle field = x m

➝ Breadth of the rectangle field = y m

$\bullet\:\underline{\textsf{As Per the Question}}$

The length of a rectangle field is twice its breadth.

≫ $\sf{x=2y\qquad -eq(1)}$

And also,The perimeter of the field is 222 m

➳ $\sf{2(x+y)=222}$

➳ $\sf{x+y =\dfrac{222}{2}}$

➳ $\sf{x+y=111}$

➳ $\sf{2y+y=111\quad\bigg\lgroup Put\:x=2y\: from\:eq(1)\bigg\rgroup}$

➳ $\sf{3y=111}$

➳ $\sf\red{y=37}$

Substituting the value of y in eq(1)

»» $\sf{x=2y}$

»» $\sf{x=2\times\:37}$

»» $\sf\orange{x=74}$

$\rule{170}3$