Math, asked by kabirchy35, 6 months ago

The length of a rectangle in twice its breadth . If the perimeter is 72 meters , find the length and breadth of the rectangle.

Answers

Answered by Anonymous
31

Answer:

l = 2b

So, perimeter of rectangle = 2 ( l + b )

=> 72 = 2 ( 2b + b ) = 2 × 3b = 6b

6b = 72 => b = 72/6 = 12

Breadth = 12 meters

Length = 2 × 12 = 24 meters


prince5132: Please correct your answer :- b = 72/6 = 12*
Answered by TheProphet
80

S O L U T I O N :

\underline{\bf{Given\::}}

The length of a rectangle is twice it's breadth. If the perimeter is 72 m .

\underline{\bf{Explanation\::}}

Let the breadth of rectangle be x & the length of rectangle be 2x respectively.

As we know that formula of the perimeter of rectangle;

\boxed{\bf{Perimeter = 2(length + breadth)}}

A/q

\longrightarrow\tt{Perimeter = 2(Length + Breadth)}

\longrightarrow\tt{72= 2(2x+ x)}

\longrightarrow\tt{72= 2(3x)}

\longrightarrow\tt{72= 6x}

\longrightarrow\tt{x = \cancel{72/6}}

\longrightarrow\bf{x = 12\:m}

Thus,

The length of rectangle will be 2 × 12 = 24 m .

The breadth of rectangle will be 1 × 12 = 12 m .

Now,

C H E C K :

→ 72 = 2(L + B)

→ 72 = 2(24 + 12)

→ 72 = 2(36)

→ 72 = 72  [checked]


prince5132: Nice !
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