Question

The length of a rectangle in twice its breadth . If the perimeter is 72 meters , find the length and breadth of the rectangle.​

Answer 1

Answer:

S O L U T I O N :

$\underline{\bf{Given\::}}$

The length of a rectangle is twice it's breadth. If the perimeter is 72 m .

$\underline{\bf{Explanation\::}}$

Let the breadth of rectangle be x & the length of rectangle be 2x respectively.

As we know that formula of the perimeter of rectangle;

$\boxed{\bf{Perimeter = 2(length + breadth)}}$

A/q

$\longrightarrow\tt{Perimeter = 2(Length + Breadth)}$

$\longrightarrow\tt{72= 2(2x+ x)}$

$\longrightarrow\tt{72= 2(3x)}$

$\longrightarrow\tt{72= 6x}$

$\longrightarrow\tt{x = \cancel{72/6}}$

$\longrightarrow\bf{x = 12\:m}$

Thus,

The length of rectangle will be 2 × 12 = 24 m .

The breadth of rectangle will be 1 × 12 = 12 m .

Now,

C H E C K :

→ 72 = 2(L + B)

→ 72 = 2(24 + 12)

→ 72 = 2(36)

→ 72 = 72  [checked]

Answer 2

Answer:

Perimeter of recatngle = 2(length+breadth)

Here it is given that length is twice of breadth

Let 'L' be the length and 'b' be the breadth then

It is given that L=2b

And as per given information

2(L+b)=72

We can replace 'L' with '2b' because it's twice of b

Then we will get

2(2b+b)=72

2(3b)=72

6b=72

b=72/6=12

Therefore Length= 2×12=24

Step-by-step explanation:

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