Question

The length of a rectangle in twice its breadth . If the perimeter is 36 meters , find the length and breadth of the rectangle.​

Answer 1

✰ Question Given :

• ➦ The length of a rectangle in twice its breadth . If the perimeter is 36 meters , find the length and breadth of the rectangle.

✰ Required Solution :

✯ Value Given to us :

• ⇢ Perimeter of rectangle = 36 m

✯ Assumption Needed :

• ⇢ let breadth of rectangle be x

• ⇢ let length of rectangle be 2x

✯ Formula used Here :

• ⇢ Perimeter = 2 ( l + B )

✯ Putting Value in Formula :

• ⇢ Perimeter = 2 ( l + B )

• ⇢ 36 m = 2 ( 2x + x )

• ⇢ 36 m = 2 × 3x

• ⇢ 36 m = 6x

• ⇢ X = 6 m

✯ Now Substituting X Value :

• For length :-

• ⇢ length = 2x

• ⇢ length = 12 m

• For Breadth :-

• ⇢ Breadth = x

• ⇢ Breadth = 6 m

✰ Therefore :

• ➦ Length of rectangle = 12 m

• ➦ Breadth of rectangle = 6 m

_______________________

Answer 2

Given :

• Length of a Rectangle is twice its breadth .
• Perimeter of the Rectangle is 36 m .

To Find :

• Length and Breadth of the Rectangle .

Solution :

$\longmapsto\tt{Let\:Breadth\:be=x}$

As Given that length of a rectangle is twice its breadth . So ,

$\longmapsto\tt{Length=2x}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{36=2(2x+x)}$

$\longmapsto\tt{\cancel\dfrac{36}{2}=3x}$

$\longmapsto\tt{18=3x}$

$\longmapsto\tt{x=\cancel\dfrac{18}{3}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{x}\orange{=}\purple{6}}}$

Therefore :

$\longmapsto\tt{Breadth\:of\:Rectangle=x}$

$\longmapsto\tt\bf{6\:m}$

$\longmapsto\tt{Length\:of\:Rectangle=2(6)}$

$\longmapsto\tt\bf{12\:m}$