Question

The length of a rectangle is 1 cm more than twice its breadth. If the perimeter of the rectangle is 50 cm, find its length.​

Answer 1

Answer:

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Answer 2

Let,

Breadth (b) = x cm

Length (l) = 2x+1 cm [1 cm more than twice its breadth]

Perimeter (P) = 50 cm

We know,

$\boxed{\bold{\sf{Perimeter \ of \ a \ rectangle=2(l+b)}}}$

Applying values to the equation:

$\sf{\implies 50=2\{(2x+1)+x\}}$

$\sf{\implies 50=4x+2+2x }$

$\sf{\implies 50=6x+2}$

$\sf{\implies 6x=50-2}$

$\sf{\implies 6x=48}$

$\sf{\implies x=\dfrac{48}{6}}$

$\sf{\implies x=8 \ cm}$

$\boxed{\sf{\therefore \ Breadth \ (b)=8 \ cm}}$

We know here 2x+1 is the length:

$\sf{\implies l=2x+1}$

$\sf{\implies l=(2\times8)+1}$

$\sf{\implies l=16+1}$

$\sf{\implies l=17 \ cm}$

$\boxed{\sf{\therefore \ Length \ (l)=17 \ cm}}$

$\huge{\boxed{\bold{\sf{\therefore \ Length=17 \ cm}}}}$